60x^2-480x-960=0

Solution for 60x^2-480x-960=0 equation:

60x^2-480x-960=0

a = 60; b = -480; c = -960;
Δ = b2-4ac
Δ = -4802-4·60·(-960)
Δ = 460800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{460800}=\sqrt{230400*2}=\sqrt{230400}*\sqrt{2}=480\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-480\sqrt{2}}{2*60}=\frac{480-480\sqrt{2}}{120}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+480\sqrt{2}}{2*60}=\frac{480+480\sqrt{2}}{120}
$